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Homework Help: Integration and differential

  1. Mar 8, 2010 #1
    1. The problem statement, all variables and given/known data
    integrate R(t) 2+5sin(4πt/25) to calculate F(t) from 0 to 6


    2. Relevant equations



    3. The attempt at a solution
    the differential equation is 2+5sin(4πt/25)
    so after the integration, i get 2t-5cos(4πt/25)(25/4π)
    so i wanna get the value in the interval from 0 to 6)

    so i put 2+5sin(4πt/25) on my calculator and made it do the integration,
    It gives me 31.8159
    but when i F(6)-F(0) on this function, 2t-5cos(4πt/25)(25/4π), i get something entirely different.
    My calculator is on radian mode and π is pie
    What am i doing wrong?
     
  2. jcsd
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