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## Homework Statement

integrate R(t) 2+5sin(4πt/25) to calculate F(t) from 0 to 6

## Homework Equations

## The Attempt at a Solution

the differential equation is 2+5sin(4πt/25)

so after the integration, i get 2t-5cos(4πt/25)(25/4π)

so i wanna get the value in the interval from 0 to 6)

so i put 2+5sin(4πt/25) on my calculator and made it do the integration,

It gives me 31.8159

but when i F(6)-F(0) on this function, 2t-5cos(4πt/25)(25/4π), i get something entirely different.

My calculator is on radian mode and π is pie

What am i doing wrong?