1. The problem statement, all variables and given/known data integrate R(t) 2+5sin(4πt/25) to calculate F(t) from 0 to 6 2. Relevant equations 3. The attempt at a solution the differential equation is 2+5sin(4πt/25) so after the integration, i get 2t-5cos(4πt/25)(25/4π) so i wanna get the value in the interval from 0 to 6) so i put 2+5sin(4πt/25) on my calculator and made it do the integration, It gives me 31.8159 but when i F(6)-F(0) on this function, 2t-5cos(4πt/25)(25/4π), i get something entirely different. My calculator is on radian mode and π is pie What am i doing wrong?