- #1

bcjochim07

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## Homework Statement

A 4 cm diameter cylinder floats in the water. How much work must be done to push the cylinder 10 cm deeper into the water?

## Homework Equations

## The Attempt at a Solution

I did the integral from 0 to .1 m of (.02m)^2 * pi * (1000kg/m^3) * (9.80) * x dx

= (12.3 x^2)/2 evaluated from 0 to .1 = .0615 J. However, the back of my book says .615 J. Somehow I ended up a decimal place off. Could someone help me?