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Integration buoyancy problem

  • Thread starter bcjochim07
  • Start date
  • #1
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Homework Statement


A 4 cm diameter cylinder floats in the water. How much work must be done to push the cylinder 10 cm deeper into the water?


Homework Equations





The Attempt at a Solution



I did the integral from 0 to .1 m of (.02m)^2 * pi * (1000kg/m^3) * (9.80) * x dx

= (12.3 x^2)/2 evaluated from 0 to .1 = .0615 J. However, the back of my book says .615 J. Somehow I ended up a decimal place off. Could someone help me?
 

Answers and Replies

  • #2
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Anyone have any thoughts on this one?
 
  • #3
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Isn't the radius=0.2 instead of 0.02 ?
 
  • #4
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no, I'm pretty sure the radius is correct

4 cm/2 = radius of 2 cm 2cm * 1m/100cm = .02 m
 
  • #5
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Any thoughts would be greatly appreciated
 
  • #6
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I think that given the values you are working with that your answer is correct.
 
  • #7
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I am concerned because the back of my book says it's .615 J and I can't figure out what's wrong with mine
 
  • #8
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Can somebody find my mistake?
 
  • #9
374
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I need some help with this one pretty soon because my homework is due tomorrow. Thanks!
 
  • #10
70
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Sometimes the answer in the book is wrong...or the problem data has been misread. In either case it looks like to me that your answer is correct, If not, I would also like to know why and maybe another reader can set us both strait.
 

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