Integration by part method

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  • Thread starter jaychay
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  • #1
jaychay
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Untitled 10.png



Can you help me with this question ?
I am really struck with this question.
Thank you in advance.
 

Answers and Replies

  • #2
skeeter
1,104
1
Using integration by parts, I would let

$u = x^3$ and $dv=x^2\sqrt{x^3+1}$


Alternatively, one could use the same setup for the method of substitution letting $t= x^3+1$
 

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