i will use "\int" as integral signs, cause latex seems to be down.(adsbygoogle = window.adsbygoogle || []).push({});

uv - \int v*du

\int 8x^2cos(2x)*dx

u = 8x^2

du = 16x*dx

dx = 1/16

dv = cos(2x)

v = 1/2sin(2x)

plug in what i found for the formula

8x^2*1/2*sin(2x) - \int 1/2*sin(2x)*16x

take out the 1/2, because it's a number.

4x^2*sin(2x) - 1/2 \int sin(2x) *16x

k this is the part where im stuck on. do i use integration by parts on the right side agian? my attempt of u-du:

u=16x

du = 16*dx

dx = 1/16

sin(1/8*u) * u

hmm... looks wrong

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# Homework Help: Integration by parts formula

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