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Integration by parts (i think)

  1. Mar 30, 2005 #1
    Greetings all,

    here goes....

    The integral of (xe^(x))/((x+1)^(2))

    Thanks
     
  2. jcsd
  3. Mar 30, 2005 #2
    [tex] \int{\frac{xe^x}{(x+1)^2}}{dx} [/tex]

    [tex] u = \frac{-1}{x+1} [/tex]

    [tex] du = \frac{1}{(x+1)^2}[/tex]

    [tex] v = xe^x [/tex]

    [tex] dv = e^x(x+1) [/tex]

    [tex] \int{v}{du} = uv - \int{u}{dv} [/tex]

    [tex] \int{\frac{xe^x}{(x+1)^2}}{dx} = \frac{-xe^x}{x+1} + \int{e^x}{dx} [/tex]

    Hope that helps you out. Not a very hard problem from there ;)
     
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