Integration by parts (i think)

1. Mar 30, 2005

PhysicsMajor

Greetings all,

here goes....

The integral of (xe^(x))/((x+1)^(2))

Thanks

2. Mar 30, 2005

whozum

$$\int{\frac{xe^x}{(x+1)^2}}{dx}$$

$$u = \frac{-1}{x+1}$$

$$du = \frac{1}{(x+1)^2}$$

$$v = xe^x$$

$$dv = e^x(x+1)$$

$$\int{v}{du} = uv - \int{u}{dv}$$

$$\int{\frac{xe^x}{(x+1)^2}}{dx} = \frac{-xe^x}{x+1} + \int{e^x}{dx}$$

Hope that helps you out. Not a very hard problem from there ;)