integration by parts!!!! MIDTERM...really quick question....please help!!!! 1. The problem statement, all variables and given/known data [tex]\int[/tex] arctan4t dt 2. Relevant equations 3. The attempt at a solution ive been attempting this all day. the answer is t arctan4t-1/8 ln(1+16t^2)+C i get this asnwer up until the 1/8....... a few steps befor emy answer i have t arctan4t - [tex]\int[/tex] 4t/ 1+16t^2 i dont kno whow to go from here to the answer....someone please help!!!