integral y(1+y^2)^1/2 dy
can someone help me with this?
Wouldn't this solve easier with u substituion?
u = 1+y^2
du = 2y dy
Solution is 1/3(1+y^2)^3/2
If you want integration by parts, multiply it out and make u to be y so that du is 1.
By trig you'll need to substitute tan because the problem is + Y^2.
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