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Integration by parts

  1. Nov 10, 2006 #1
    integral y(1+y^2)^1/2 dy

    can someone help me with this?

  2. jcsd
  3. Nov 10, 2006 #2
    trigonometirc sub.
  4. Nov 10, 2006 #3
    Wouldn't this solve easier with u substituion?
    u = 1+y^2
    du = 2y dy

    Solution is 1/3(1+y^2)^3/2

    If you want integration by parts, multiply it out and make u to be y so that du is 1.

    By trig you'll need to substitute tan because the problem is + Y^2.

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