Use integration by parts to evaluate the integral:
∫ 1 ÷ (16 + x2) dx
∫ u dv = uv - ∫ v u' du
The Attempt at a Solution
That's the problem, I don't know how to start. How would I divide up 1/(16 + x2) into two? So there would be a value for u and v'.
Maybe this isn't so much a question of how do you solve the integral, but how do you split the above polynomial. There's also tan in the answer, but I'm not sure how to get to that.
Any help to point me in the right direction would be greatly appreciated.