- #1

- 11

- 0

thanks

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- Thread starter mpgcbball
- Start date

- #1

- 11

- 0

thanks

- #2

- 13,033

- 588

[tex] \int \arctan \frac{1}{x} {} dx =x\arctan \frac{1}{x}-\int x \frac{-\frac{1}{x^2}}{1+\frac{1}{x^2}} {} dx [/tex]

- #3

- 11

- 0

- #4

- 132

- 1

Take it to be 1* arctan(...) then your dv will be 1.

- #5

- 11

- 0

- #6

- 11

- 0

ooooh i get it!! thank you

- #7

- 11

- 0

im still getting stuck at xarctan(1/x)-int(-x/x^2+1)

- #8

- 13,033

- 588

Can you then integrate

[tex] \int \frac{x}{x^2 +1} {}dx [/tex]

?

[tex] \int \frac{x}{x^2 +1} {}dx [/tex]

?

- #9

- 132

- 1

[tex] \int \frac{x}{x^2 +1} {}dx [/tex]

- #10

- 184

- 0

what is the derivative of [tex]\ln(x^2 + 1) [/tex] ?

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