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## Homework Statement

[tex]\int[/tex] t sin(2t) dt

## Homework Equations

Integration by parts formula:

[tex]\int[/tex]udv = uv - [tex]\int[/tex]vdu

## The Attempt at a Solution

I chose t to be u so,

u=t

du=dt

dv=sin(2t)dt

v=(sin)^2 (hope that's right. I used double angle formula to change sin(2t) into 2sint cost)

So now by the integration by parts formula I get:

[tex]\int[/tex]t sin(2t)dt = t(sint)^2 - [tex]\int[/tex](sint)^2 dt

Now I have no idea how to integrate sin

^{2}t

I don't know if I messed up somewhere way up there or if it's right and I'm just stuck on this part. Any help would be greatly appreciated. Thanks in advance!