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Integration by parts

  1. Oct 23, 2011 #1
    1. The problem statement, all variables and given/known data
    Solve integral
    [tex]\int^{1}_0(1-x)\frac{d}{dx}\frac{\sin Cx}{C}dx[/tex]

    2. Relevant equations

    [tex]\int udv=uv-\int vdu[/tex]



    3. The attempt at a solution

    [tex]u=1-x[/tex]

    [tex]dv=\frac{d}{dx}\frac{\sin Cx}{C}dx[/tex]

    What is [tex]v[/tex]?

    How to integrate

    [tex]\frac{d}{dx}\frac{\sin Cx}{C}dx[/tex]?
     
  2. jcsd
  3. Oct 23, 2011 #2

    Mark44

    Staff: Mentor

    Is C a constant?

    Why not just differentiate sin(Cx)/C?
     
  4. Oct 23, 2011 #3

    dynamicsolo

    User Avatar
    Homework Helper

    What is the anti-derivative of a derivative?
     
  5. Oct 23, 2011 #4

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    Fundamental Theorem of Calculus!
     
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