1. Sep 4, 2012 #1

   Bashyboy

   

   I understand this integration technique, for the most part. One thing I am curious to know is why, when you do your rudimentary substitution for this particular technique, does dv have to always include dx?

    

   Bashyboy, Sep 4, 2012
2. 
   Phys.org - latest science and technology news stories on Phys.org

   • • Game over? Computer beats human champ in ancient Chinese game
   • • Simplifying solar cells with a new mix of materials
   • • Imaged 'jets' reveal cerium's post-shock inner strength
3. Sep 4, 2012 #2

   HallsofIvy

   

   Staff Emeritus

   Science Advisor

   "Integration by parts" is just the integral version of the "product rule" for derivatives:
   d(uv)= udv+ vdu. We can write that as udv= d(uv)- vdu and integrate both sides:
   [itex]\int udv= \int d(uv)- \int vdu[/itex]. Of course, [itex]\int d(uv)= uv[/itex].
   
   As for "does dv have to always include dx?", yes, of course. "dv" is a differential and you cannot have an "ordinary" function equal to a differential. A differential can only be equal to another differential.

    

   HallsofIvy, Sep 4, 2012
4. Sep 4, 2012 #3

   Bashyboy

   

   Is there a reason for this? Or have mathematicians defined this to be true?

    

   Bashyboy, Sep 4, 2012

• Log in with Facebook
• Log in with Twitter

Your name or email address:

Do you already have an account?

• No, create an account now.
• Yes, my password is:
• Forgot your password?

Stay logged in