# Integration by sketching

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1. Sep 7, 2015

### wirefree

I greatly appreciate this chance to submit a query.

I have the following integral: $$\int_{1}^t 2sin(t-\tau)e^{-2(t-1)} d\tau$$

and it has been suggested to me that if I sketch the two constituent functions and multiply them, I can read the answer off the paper. So here are my sketches: go straight to the 3rd arrow

Don't let alternative integral side-track you; it involves something called "convolution" and is something I am grappling with too.

My firtst attempt: There is clearly some area under the graphs, so the answer is not 0. The alternatives I have are: 0, 1 or 2. But, surely, that's not something I can read that off the graph?

My second attempt: I just did the integral by taking $$2e^{-2(t-1)}$$ out; but that simply integrates down to an expression in terms of 't', and without any value of 't' I can't see how a definite answer can be obtained.

I think you can put outside the integral the factors without $\tau$ so you can integrate $\int_{1}^{t}\sin{(t-\tau)}d\,\tau$ that is elementary, you obtain in this way an Area function that depends only by $t$.