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Integration by Substituion

  1. Oct 12, 2006 #1
    Can anyone help me with the following integrals (integrate by substitution)?

    \int{\frac{dx}{\sqrt{x^2 - 4}}}

    \int{\frac{dx}{\sqrt{x^2 + 4}}}

    I have no idea whatsoever on how to do it.
  2. jcsd
  3. Oct 12, 2006 #2
    [tex] \int{\frac{dx}{\sqrt{x^2 - 4}}} [/tex]. Use the substitution [tex] x = 2\sec \theta [/tex]

    \int{\frac{dx}{\sqrt{x^2 + 4}}}
    [/tex] Use the substitution [tex] x = 2\tan \theta [/tex]
  4. Oct 12, 2006 #3
    Right, thanks a lot :D
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