I am going crazy on this problem:(adsbygoogle = window.adsbygoogle || []).push({});

[tex] \int sec(v+(\pi/2)) tan(v+\pi/2)) dv [/tex]

if I substitute u= [tex] tan(v+\pi/2)) dv [/tex], can I use the product rule to find du= [tex] sec(v+(\pi/2)) dv [/tex].

Thanks, Todd

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# Homework Help: Integration by substitution help

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