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How do you do this question, Ive spent hours figuring it out:
Use the substitution x = 3sint to show that
3
[inte]x^2[squ](9-x^2) dx = (81/16)pi
0
Use the substitution x = 3sint to show that
3
[inte]x^2[squ](9-x^2) dx = (81/16)pi
0