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I am having difficulty with one aspect of intergration by substitution where the substituion of a square root is U^2, wondering if anyone can help.

Problem:

Integral of: 2x√(3x-4) dx by substituting U^2 = 3x-4

Would du^2/dx = 3 therefore 1/3 du^2 = dx (I think this is where im going wrong)

Im coming out with an answer of: 2/45(9x+8)(3x-4)^3/2 + k

However the answer in the book is: 4/135(9x+8)(3x-4)^3/2 + k

Any help would be greatly appreciated.

Regards

Dave

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# Homework Help: Integration by substitution

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