Integration by substitution

1. Nov 11, 2011

aub

can someone please explain to me the yellow area?

2. Nov 11, 2011

JHamm

The first line sets up the substitution of u in place of $\log _e (z)$, the next line takes the derivative of each side and the final line rearranges for an expression for $dz$; then these can be used to change the integrand :)

3. Nov 15, 2011

aub

ok thanks
did well on the exam btw :)