- #1

badtwistoffate

- 81

- 0

let x= 2 tan(q)

i get 1/(4 tan^2(q) + 4)^2

I get 1/ (16 tan ^4(q) + 32 (1-sec^2(q) + 16)

and now i think about doing a u-substituition with tan x=u, du =sec^2 (x) can i do that!?!

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- Thread starter badtwistoffate
- Start date

- #1

badtwistoffate

- 81

- 0

let x= 2 tan(q)

i get 1/(4 tan^2(q) + 4)^2

I get 1/ (16 tan ^4(q) + 32 (1-sec^2(q) + 16)

and now i think about doing a u-substituition with tan x=u, du =sec^2 (x) can i do that!?!

- #2

badtwistoffate

- 81

- 0

do you just don't like my topics i want help in?

- #3

whozum

- 2,221

- 1

[tex] \frac{1}{(4\tan(q)+4)^2} = \frac{1}{16\sec^4q} [/tex]

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