• Support PF! Buy your school textbooks, materials and every day products Here!

Integration/calc work? what did i do wrong

  • #1
Int[1/(x^2+4)^2]
let x= 2 tan(q)
i get 1/(4 tan^2(q) + 4)^2
I get 1/ (16 tan ^4(q) + 32 (1-sec^2(q) + 16)
and now i think about doing a u-substituition with tan x=u, du =sec^2 (x) can i do that!??!?!?! :surprised :mad:
 

Answers and Replies

  • #2
do you just dont like my topics i want help in?
 
  • #3
2,209
1
[tex] \frac{1}{(4\tan(q)+4)^2} = \frac{1}{16\sec^4q} [/tex]
 

Related Threads for: Integration/calc work? what did i do wrong

  • Last Post
Replies
4
Views
1K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
10
Views
1K
  • Last Post
Replies
6
Views
997
Replies
4
Views
825
  • Last Post
Replies
0
Views
2K
Top