- #1
UrbanXrisis
- 1,196
- 1
[tex]\frac{dy}{dt}=ky[/tex]
I need to solve for y
[tex]\int\frac{dy}{y}=k \int dt[/tex]
[tex]ln(y)=kt[/tex]
[tex]y=e^{kt} +C[/tex]
is this correct? also, I've always wondered why the integral of [itex]dy[/itex] goes away? the integration of [itex]dx[/itex] becomes x, but what about dy? Also, if I were to integrate x^2 dx... the dx goes away after that integratin as well, why is that?
I need to solve for y
[tex]\int\frac{dy}{y}=k \int dt[/tex]
[tex]ln(y)=kt[/tex]
[tex]y=e^{kt} +C[/tex]
is this correct? also, I've always wondered why the integral of [itex]dy[/itex] goes away? the integration of [itex]dx[/itex] becomes x, but what about dy? Also, if I were to integrate x^2 dx... the dx goes away after that integratin as well, why is that?