- #1

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## Homework Statement

[tex]\int dx/(e^{x}\sqrt{1-e^{-2x}}) [/tex]

## Homework Equations

## The Attempt at a Solution

I have absolutely no idea of how to start the problem, any help is greatly appreciated!

thanks!

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- Thread starter physnoob
- Start date

- #1

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[tex]\int dx/(e^{x}\sqrt{1-e^{-2x}}) [/tex]

I have absolutely no idea of how to start the problem, any help is greatly appreciated!

thanks!

- #2

rock.freak667

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- #3

Mark44

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Also, note that 1/e^{x} = e^{-x}.

- #4

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e[tex]^{-2x}[/tex]? I have tried do a u sub. of u = [tex]\sqrt{1-e^{-2x}}[/tex], but i ended up getting the [tex]\int du/e^{-x}[/tex], which i dont know how to proceed after this. What am i doing wrong?

- #5

rock.freak667

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e^{-2x}=(e^{-x})^{2}, so in terms of u it is?

- #6

Mark44

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Doesn't e^{-x}*e^{-x} = e^{-2x}?

- #7

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just want to make sure, is the answer cos[tex]^{-1}[/tex](e[tex]^{-x}[/tex]) + C?

- #8

rock.freak667

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That should be correct.

I think -sin^{-1}(e^{-x})+C should work as well.

I think -sin

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