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Integration formulae for a tetrahedron

  1. May 24, 2009 #1
    Hello everybody!
    I am trying to formulate a mathematical approach using Finite Element Method in an Electromagnetic problem in conjunction with Floquet theorem. Due to the fact I use tetrahedral elements, some definite integrals have been appeared. The fact is that I can compute analytically these integrals.

    To be more specific letting a tetrahedron be defined in the x,y,z coordinate system by four point (x1,y1,z1),(x2,y2,z2),(x3,y3,z3),(x4,y4,z4) and the origin of the coordinates taken at the centroid we have:

    Then integrating over the tetrahedron volume gives:
    \int{dxdydz}=\frac{1}{6} \begin{vmatrix} 1 & x_{1} & y_{1} & z_{1} \\ 1 & x_{2} & y_{2} & z_{2} \\ 1 & x_{3} & y_{3} & z_{3} \\ 1 & x_{4} & y_{4} & z_{4} \end{vmatrix}=V \rightarrow \quad \textrm{tetrahedron volume}
    Moreover some useful integral quantities are:
    \int{xdxdydz}=&\int{ydxdydz}=\int{zdxdydz}=0 \\
    \int{x^{2}dxdydz}=&\frac{V}{20}(x_{1}^{2}+x_{2}^{2}+x_{3}^{2}+x_{4}^{2})=\frac{V}{20}\sum_{i=1}^{4}x_{i}^{2} \\
    \int{y^{2}dxdydz}=&\frac{V}{20}(y_{1}^{2}+y_{2}^{2}+y_{3}^{2}+y_{4}^{2})=\frac{V}{20}\sum_{i=1}^{4}y_{i}^{2} \\
    \int{z^{2}dxdydz}=&\frac{V}{20}(z_{1}^{2}+z_{2}^{2}+z_{3}^{2}+z_{4}^{2})=\frac{V}{20}\sum_{i=1}^{4}z_{i}^{2} \\
    \int{xydxdydz}=&\frac{V}{20}(x_{1}y_{1}+x_{2}y_{2}+x_{3}y_{3}+x_{4}y_{4})=\frac{V}{20}\sum_{i=1}^{4}x_{i}y_{i} \\
    \int{yzdxdydz}=&\frac{V}{20}(y_{1}z_{1}+y_{2}z_{2}+y_{3}z_{3}+y_{4}z_{4})=\frac{V}{20}\sum_{i=1}^{4}y_{i}z_{i} \\

    However, applying Floquet theorem, the integrals above are multiplied by [tex]e^{-j\beta{x}}[/tex].
    Can anybody give me a hint how exactly these integrals can be computed?

  2. jcsd
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