- #1
Lorentz_F
- 5
- 0
Why hello,
I have come across the surface integral [tex]\int\int(\frac{xz}{\sqrt{16-x^{2}}+x})dzdx[/tex]
My query is, which type of integration do I use to solve the first part of this double integral. The solution is: [tex]\int(4x+8)dz[/tex] = 90
I have come across the surface integral [tex]\int\int(\frac{xz}{\sqrt{16-x^{2}}+x})dzdx[/tex]
My query is, which type of integration do I use to solve the first part of this double integral. The solution is: [tex]\int(4x+8)dz[/tex] = 90