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Integration help

  1. Dec 9, 2008 #1


    (integral sign)= (x+1/x+2)+3
  2. jcsd
  3. Dec 9, 2008 #2


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    Gold Member

    If (x+1/x+2) is one term (not sure you have written it correctly), ((x+1/x+2)^2)/2 +3x

    You raise the term to the next power and divide the whole thing by that power.
  4. Dec 9, 2008 #3


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    Dead wrong. Differentiate that and use the chain rule. It doesn't work. You have to integrate each term separately. Integrate x, 1/x, 2 and 3 and add the results.
  5. Dec 9, 2008 #4


    Staff: Mentor

    What exactly is the problem? "(integral sign) = <whatever>" makes no sense to me. Is this the problem?
    [tex]\int (\frac{x + 1}{x + 3} + 3)dx[/tex]

    Or is this it?
    [tex]\int (x + 1/x + 2 + 3)dx[/tex]
    I suspect that this is not what you meant, although Dick interpreted what you wrote that way.

    If the first integral is the one you meant, you'll need to divide (x + 1) by (x + 2), which will give you 1 + (some number)/(x + 2).
  6. Dec 9, 2008 #5
    to thread starter :
    if it is the first integral that Mark is referring to, you should most probably get 4x-ln(x+2)
  7. Dec 9, 2008 #6


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    I'm not sure giving the answer is really the way we give help here, is it?
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