# Integration help

## Homework Statement

Integral of 1/(x^2+sqrt(x)) dx

## The Attempt at a Solution

i tried u=sqrt(x)
so then 2udu=dx
u^2=x

so then 2 integral u/(u^4+u) du

then integral 2/(u^3+1)du then i factored it with sum of cubes then i did partial fraction's
on it is this the right approach.

Dick
Homework Helper
Seems fine to me so far.

but when i do the partial fractions after i factor the sum of cubes i get an unfactorable quadratic and i can't get the terms to cancel out with out the other cancilind out to find out the leading co-effiecients of the numertors of the partial fractions.

Dick
Homework Helper
Yes, you do get an irreducible quadratic. Complete the square in the denominator and use a trig substitution.

we havn't learned trig substitution yet.

Dick