• Support PF! Buy your school textbooks, materials and every day products Here!

Integration help

  • Thread starter kartoshka
  • Start date
  • #1
5
0
[itex]\int[/itex] [itex]\frac{e^{\sqrt{x}}}{\sqrt{x}}[/itex]


It's in the substitution rule/symmetric function section of my book, so I figure I probably have to use one of those techniques to solve it. I've tried doing a bunch of different u substitutions [itex]\sqrt{x}[/itex], [itex]e^{{\sqrt{x}}}[/itex], etc, but none of them seem right.

How can you tell if a function is symmetric by looking at the equation? And whether it is even or odd?

PS - couldn't figure out how to do it, but it's actually a definite integral that goes from 1 to 4. Also, if the top of the fraction is hard to read, it's [itex]e^{{\sqrt{x}}}[/itex].
 

Answers and Replies

  • #2
258
0
Try [tex]u = \sqrt{x}[/tex] again.
 
  • #3
5
0
Well now I feel a bit ridiculous. But I end up with [itex]/int[/itex]e^u * u^-2. Is there a way to solve this without integration by parts? We haven't gotten to it yet so I feel like there should be a way.

Sorry for the lack of formatting, typing on my phone and I can't remember most of the tags.
 
  • #4
SammyS
Staff Emeritus
Science Advisor
Homework Helper
Gold Member
11,315
1,005
If [itex]u = \sqrt{x}\,,[/itex] then what is du ?

BTW: It's important to have the dx in the integral: [itex]\displaystyle \int\frac{e^{\sqrt{x}}}{\sqrt{x}} dx\,.[/itex]
 

Related Threads on Integration help

  • Last Post
Replies
18
Views
1K
  • Last Post
Replies
1
Views
610
  • Last Post
Replies
17
Views
2K
  • Last Post
Replies
2
Views
962
  • Last Post
Replies
4
Views
1K
  • Last Post
Replies
7
Views
777
  • Last Post
Replies
8
Views
1K
  • Last Post
Replies
10
Views
1K
  • Last Post
Replies
15
Views
2K
  • Last Post
Replies
5
Views
2K
Top