# Integration Homework Help

1. May 3, 2008

### MillerL7

A population of cattle is increasing at a rate of 200 + 10t per year, where t is measured in years. By howmuch does the population increase between the 4th and 6th years. What is the total increase?

I tried using integration, and have b=6 and a=4, with interval of 2, but it was wrong. Please help me. Thank you!

2. May 3, 2008

### Crazy Tosser

$$P(t) = \int (200+10t)dt = 200t+ 5t^2$$
$$P(6)-P(4)=?$$

If you did that and you got it wrong, i really don't know....

3. May 3, 2008

### MillerL7

thank you! that is correct, I understand that one now