Integration Homework Help

  • Thread starter MillerL7
  • Start date
  • #1
14
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A population of cattle is increasing at a rate of 200 + 10t per year, where t is measured in years. By howmuch does the population increase between the 4th and 6th years. What is the total increase?

I tried using integration, and have b=6 and a=4, with interval of 2, but it was wrong. Please help me. Thank you!
 

Answers and Replies

  • #2
176
0
[tex]P(t) = \int (200+10t)dt = 200t+ 5t^2[/tex]
[tex]P(6)-P(4)=?[/tex]

If you did that and you got it wrong, i really don't know....
 
  • #3
14
0
thank you! that is correct, I understand that one now
 

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