Integration of arctan(u)

  • Thread starter trajan22
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  • #1
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hi im having trouble integrating arctan(u).

i have no idea where to even start. i know the derivative of arctan is
[tex] \frac{1}{x^2+1} [/tex] so i would assume that the integral would be the opposite?
but i am supposed to prove that [tex] (arctan(u))=u(arctan(u))-\frac{1}{2}ln(1+u^2)+C [/tex]

i am completely lost please help...any input is much appreciated.
 

Answers and Replies

  • #2
arildno
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Remember:
[tex]arctan(u)=1*arctan(u)[/tex]
:smile:
 
  • #3
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so then you are saying that by using integration by parts i should be able to prove this?
 
  • #4
arildno
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Yep, that does the trick! :smile:
 
  • #5
Gib Z
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hehe I was thinking that to, love that trick. I need to learn where to use it though, sometimes it leads me off to nowhere..
 
  • #6
arildno
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hehe I was thinking that to, love that trick. I need to learn where to use it though, sometimes it leads me off to nowhere..

But blundering about is a far better thing to do than not dare to commit anything to paper..:smile:
 
  • #7
Gib Z
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Of Course :D
 

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