Hi,(adsbygoogle = window.adsbygoogle || []).push({});

Need help desperately!

I am trying to figure out the area under a gaussian cone by finding the integral of

2PIArEXP[-(r^2)/(2sigma^2)] dr

My supervisor thought it is

2PI [A sigma^2 EXP(-(r^2)/(2 sigma^2)] Between 0 and infinity

and he came up with the answer

2 PI A sigma^2

I hope you can understand that!

I don't think that his integration is right to get to the second step there. But I'm not sure why. I don't think sigma will come down like that. Please help me. I haven't done maths like this for a few years and I'm very rusty at it!

Thanks

Kek

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# Integration of Gaussian equation

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