- #1
kekly
- 6
- 0
Hi,
Need help desperately!
I am trying to figure out the area under a gaussian cone by finding the integral of
2PIArEXP[-(r^2)/(2sigma^2)] dr
My supervisor thought it is
2PI [A sigma^2 EXP(-(r^2)/(2 sigma^2)] Between 0 and infinity
and he came up with the answer
2 PI A sigma^2
I hope you can understand that!
I don't think that his integration is right to get to the second step there. But I'm not sure why. I don't think sigma will come down like that. Please help me. I haven't done maths like this for a few years and I'm very rusty at it!
Thanks
Kek
Need help desperately!
I am trying to figure out the area under a gaussian cone by finding the integral of
2PIArEXP[-(r^2)/(2sigma^2)] dr
My supervisor thought it is
2PI [A sigma^2 EXP(-(r^2)/(2 sigma^2)] Between 0 and infinity
and he came up with the answer
2 PI A sigma^2
I hope you can understand that!
I don't think that his integration is right to get to the second step there. But I'm not sure why. I don't think sigma will come down like that. Please help me. I haven't done maths like this for a few years and I'm very rusty at it!
Thanks
Kek