- #1

- 2

- 0

**1/√(2πσ^2) ∫ln(x) * exp{-(x-μ)^2 / (2σ^2)} dx**

After one-step (integration by parts) it looks like the following:

**lnx + ∫ σ/(√2π) * exp[{-(x-μ)^2 / (2σ^2)} / {x (x-μ)}] dx**

After another-step (by parts), it looks like the following:

**lnx + ∫ 1/(√2πσ^2) * exp[{-(x-μ)^2 / (2σ^2)} / {x^2}] dx**

I don't think I am doing it right. Could anybody please throw some lights or may be alternative ways to achieve it?