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I Integration of Sin(x)

  1. Mar 5, 2016 #1
    Hi All,

    This is a very elementary question but, from calculus :

    ∫sinx dx from 0 to pi = 2, but i thought of it, in terms of the attached driagram.
    upload_2016-3-5_19-42-31.png

    And if we think of it, this way, the integration is the area of a half circle of radius one and is equal to Pi/2.

    Where did i go wrong ?
     
  2. jcsd
  3. Mar 5, 2016 #2

    blue_leaf77

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    No, it's not. Your mistake was to assume ##x## as the coordinate in the horizontal line, when it's actually the angle subtended between the line and the horizontal axis.
     
  4. Mar 5, 2016 #3
    You are right, thanks. the integration would be ∫(sinx)2 dx which is Pi/2.
     
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