- #1

antiflag403

- 45

- 0

I can't seem to figure out how to do this integral. If anyone could help that would be great. I would appreciate some hints/advice, rather than just the answer. Thanks!

The question is:

Evaluate the indefinite integral:

(4sin(x)+3tan(x))dx

Ok... So i know you can take the integral of each term seperatly because it is a sum and that is a principle of integrals... so i get the first part to be -4cos(x). However I am not sure how to evalue the antiderivative of 3tan(x). If anyone could help that would be great!

Thanks again.