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Homework Help: Integration problem

  1. Apr 23, 2006 #1
    It seems quite simple actually. But I'm still stuck:

    [tex]\int_{0} ^ {2\Pi} sin^3\Phi d\Phi [/tex]

    Can anyone help?
     
  2. jcsd
  3. Apr 23, 2006 #2

    HallsofIvy

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    Science Advisor

    That's a standard "sine or cosine to an odd power" integral.
    [tex]sin^3\Phi d\Phi= (sin^2\Phi)(sin\Phi)d\Phi= (1- cos^2\Phi)(sin \Phi d\Phi)[/tex]
    See any simple substitution you can use?
     
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