Integration problem

  • Thread starter ElDavidas
  • Start date
  • #1
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It seems quite simple actually. But I'm still stuck:

[tex]\int_{0} ^ {2\Pi} sin^3\Phi d\Phi [/tex]

Can anyone help?
 

Answers and Replies

  • #2
HallsofIvy
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That's a standard "sine or cosine to an odd power" integral.
[tex]sin^3\Phi d\Phi= (sin^2\Phi)(sin\Phi)d\Phi= (1- cos^2\Phi)(sin \Phi d\Phi)[/tex]
See any simple substitution you can use?
 

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