Sorry this is the first time using this forum.. so I'm not too good with writing out the equations 1. The problem statement, all variables and given/known data Find the area of the region between the curves f(x) = 3x^2 and g(x) = sqrt(x/3) for 0 <= x <= 1. 2. Relevant equations 3. The attempt at a solution So.. since g(x) is greater than f(x) from 0 to 1/3, and less from 1/3 to 1. I set up the integrals [int. from 0 to 1/3 of g(x) - int. from 0 to 1/3 of f(x)] + [int. from 1/3 to 1 of f(x) - int. from 1/3 to 1 of g(x)] Is that set up correctly? Next is where my problem is... integral of 3x^2 is x^3, but how do I integrate sqrt(x/3) ? I used the power rule and got [2(x/3)^3/2]/3, but that doesn't seem right, please help me out with this. Thanks!