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## Homework Statement

[tex]\int \frac{2e^{2t}*dt}{e^{4t}+12e^{2t}+32}[/tex]

## The Attempt at a Solution

I factored the denominator, getting (e

^{2t}+4)(e

^{2t}+8), from that I was able to express the original equation in terms of two fractions:

[tex]\int \frac{A}{e^{2t}+4}[/tex]+[tex]\frac{B}{e^{2t}+8}[/tex]

I then found A to be -2 and B=4.

But when I put those back into the original equations, I still have integrals that have an 'e' on the bottom and I don't know what to do next...

Any help is appreciated.