The Attempt at a Solution
I factored the denominator, getting (e2t+4)(e2t+8), from that I was able to express the original equation in terms of two fractions:
I then found A to be -2 and B=4.
But when I put those back into the original equations, I still have integrals that have an 'e' on the bottom and I don't know what to do next...
Any help is appreciated.