- #1

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## Homework Statement

I was given that [tex]\int \frac{m}{mgsin\alpha-kv} dv = -\frac{m}{k}ln(mgsin\alpha-kv) + C[/tex]

..but I can't 'see' how this was done.

## Homework Equations

## The Attempt at a Solution

My first thought is that this is somehow related to the fact that:

[tex]\int \frac{g'(x)}{g(x)}=ln \left|(g(x)) \right|[/tex]

but I am still missing something to make this work.

All help appreciated.