Integration problem

  • Thread starter sdoug041
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  • #1
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Homework Statement



[tex]\int[/tex]10/(x-1)(x^2-9)

Homework Equations





The Attempt at a Solution



I believe I should integrate by partial fractions here, but I'm not entirely sure on the notation. I've seen examples in my textbook that sometimes use B as opposed to Bx. Is this when that notation corresponds to a x^2?

Can this be done without having a factor of x in the numerator? If so would I just stick a +0x in the numerator before I seperate?
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
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x2-9 can be factored as (x-3)(x+3)

if you had

[tex]\frac{1}{x-A)(ax^2+bx+c)}[/tex]

and b2-4ac<0 i.e no real roots then the fractions would be

[tex]\frac{F}{x-A}+\frac{Gx+H}{ax^2+bx+c}[/tex]
 

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