How to you integrate (x2-5)1/2
The Attempt at a Solution
I have tried substitution, integration by part, and none seems to work. I really don't know where to start.
How did you get this substitution? Hyperbolic function is not in my school syllabus. Is there any other form of substitution to to solve this question?
\int tan\theta tan\theta sec\theta d\theta
put t = [tex] sec\theta [/tex]
therefore dt = [tex] sec\theta tan\theta d\theta [/tex]
draw a right angled triangle.... using t = [tex] sec\theta[/tex].. you'll get value of two sides... find the value of the third side by pythagoras theorem... that way now you can find [tex] tan\theta [/tex]
put the value of [tex] tan\theta [/tex] and dt in the integrand..... solve !
sorry i had made a mistake... i forgot the root sign..... but i think this time i got it correct..
could you please check it for me...
PS: moderators... i m not posting the solution... i am actually checking if what i've done is correct...