Integration problem

  • Thread starter tomwilliam
  • Start date
  • #1
135
2

Homework Statement


I'm trying to do this problem from S. P. Thomson's Calculus Made Easy
(see attached image file)


Homework Equations





The Attempt at a Solution


I've produce the answer here, but it seems to be different from the mathcad solution, which is:
ln(-1+x)+ln(1+x)-ln(1+x^2)

Could someone help me see if (and if so, how) my answer is equivalent (without the constant). If it's wrong, I'd appreciate a pointer as to why, and if there is a quicker way of tackling this problem than by using partial fractions, could you let me know?
Thanks in advance
 

Attachments

  • ex 004.jpg
    ex 004.jpg
    24.5 KB · Views: 310

Answers and Replies

  • #2
311
1
Your answer is correct as is the books. ln a + ln b = ln (ab).
 
  • #3
HallsofIvy
Science Advisor
Homework Helper
41,833
964
In fact, both answers could be written as
[tex]ln\left(\frac{x^2-1}{x^2+1}\right)+ C[/tex]
or even
[tex]ln\left(C'\frac{x^2-1}{x^2+1}\right)[/tex]
where C= ln(C')
 
  • #4
135
2
Thanks! Nice to get one right for a change...
 

Related Threads on Integration problem

  • Last Post
Replies
4
Views
1K
  • Last Post
Replies
1
Views
610
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
4
Views
1K
  • Last Post
Replies
13
Views
1K
  • Last Post
Replies
10
Views
1K
  • Last Post
Replies
4
Views
1K
  • Last Post
Replies
2
Views
582
  • Last Post
Replies
1
Views
656
  • Last Post
Replies
8
Views
1K
Top