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Integration Problem.

  1. Feb 26, 2005 #1
    integrate ln(tanx)/sinxcosx dx
    I want to change to integrate csc2x ln(tanx) dx , still can't work it out.
    Any suggestions?
  2. jcsd
  3. Feb 26, 2005 #2


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    [tex]\int \frac{\ln(\tan x)}{\sin x\cos x} dx [/tex] can be integrated very easily if u multiply both the denominator & the numerator by \cos x and make the substitution \tan x -------->u and then a simple part integration...

  4. Feb 26, 2005 #3
    Or you could try the substitution u = ln(tan(x)).
  5. Feb 26, 2005 #4
    Thanks so much. I got it!
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