Integration problem

1. Apr 13, 2013

gl0ck

Hello, Is this the right way to compute this integral. I get the answer from the book, but I am not sure if I've done it right.

Thanks

PS Sorry for the upside down image :)
Now should be alright

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Last edited: Apr 13, 2013
2. Apr 13, 2013

LCKurtz

3. Apr 13, 2013

LCKurtz

I have no idea what those symbols around the $x$ mean nor can I follow your steps. In particular you can't take the antiderivative of just part of the integrand.

4. Apr 13, 2013

gl0ck

This is how its written in the book..

5. Apr 13, 2013

LCKurtz

So you are trying to work a problem where you don't know and can't tell us what the symbols mean? Better read that book a bit more closely and get back to us...

6. Apr 13, 2013

gl0ck

So, if the found value is 0.6 and it is surrounded by these strange brackets this is equal to 1, if the brackets are turned other way around 0.6 is equal to 0

7. Apr 13, 2013

LCKurtz

I'm guessing that $\lfloor x \rfloor$ stands for the greatest integer less than or equal to $x$. Surely your text must define that symbol. You need to look it up and get it correct to use it in your integral. Your original integration attempt was nonsense. How could you possibly expect to get a correct antiderivative of a function when you don't know what it is in the first place? Start over.

8. Apr 13, 2013

Infrared

The best way to do this integral would be to write $\int_0^3= \int_0^1+\int_1^2+\int_2^3$ since the greatest integer function is constant on [0,1),[1,2), and [2,3). Also, I do not understand what your solution was. It seemed as though you thought that ∫fg=∫f∫g which is not true.