# Integration problem

1. Nov 30, 2013

### Dumbledore211

1. The problem statement, all variables and given/known data

∫dx/a^2sin^2x+b^2cos^2x

2. Relevant equations

3. The attempt at a solution
Okay, I attempted to solve this integral analytically but I couldn't. I tried to solve this by using trig identities like (1+cos2x)/2 and (1-cos2x)/2 but it got even more complicated. Can any of you drop a hint as to how it should be done

2. Nov 30, 2013

### vela

Staff Emeritus
3. Dec 1, 2013

### Dumbledore211

The whole denominator thing seems very complex for me to solve. How can I convert the denominator into a solvable numerator considering that the cos^2x is linked with b^2. Even if I take the U substitution route by considering u=tanx how do i deal with b^2cos^2x. How about I use the trig identity tan(x/2)/1+tan^2x/2=sinx and cosx= 1-tan^x/2/1+tan^x/2 then consider u=tanx/2 then we have it's derivative 1(1+tan^2x/2)/2=sec^2x/2/2

4. Dec 1, 2013