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Integration Problems

  1. Mar 11, 2008 #1
    I am not sure exactly what is happening between the first part and second part. What happens to the 2?

    Also, what technique do you use to integrate after that? I am a little unsure as to what slick moves are being used here. Any help is appreciated.

  2. jcsd
  3. Mar 11, 2008 #2
    I don't understand the context this is in but it looks like the 2r(dr) is being replaced by the substitution d(r^2) = 2r(dr) (this resembles usub, but i've never encountered this before). The denominator in the first step is just brought up top with a negative exponent. From step two to three, it looks like polynomial integration.

    Hmm are you learning electromagnetism right now?
  4. Mar 11, 2008 #3
    Yep electromagnetism. It is out of the first chapter on the subject in Serway and Jewett. The example is for finding the electric field on a disk.

    I am really stuck on that two, it seems like it has to be a mistake. There is probably some perspective I am missing here, that dr*2r=dr^2, but I am not seeing it now.

    I can work it out fine with a substitution, but I really like to understand everything I encounter, and this doesn't mesh well.
    Last edited: Mar 11, 2008
  5. Mar 11, 2008 #4
    If you let u = r^2, then you would replace 2rdr with du, wouldn't you?
    Here, they have just not bothered renaming r^2.
  6. Mar 11, 2008 #5
    Perfect, yep that is the angle I was missing. Of course I made the substitution u=x^2 +r^2 so du=2rdr. So thinking this way, keep going du=d(x^2+r^2)=d(r^2) etc.

    Thank you for the advice.
    Last edited: Mar 11, 2008
  7. Mar 11, 2008 #6
    It's kind of an abuse of notation. What's d(r^2)? It's the differential of r^2, which equals 2r dr.
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