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## Homework Statement

Integrate the following: ∫[1/(x^2 - 2x + 4)]dx

## Homework Equations

∫[1/(x^2 + a^2)]dx = [1/a](arctan(x/a)) + C

## The Attempt at a Solution

Let A = x^2 - 2x + 4 = x^2 - 2x + 1 + 3

= (x - 1)^2 + (√3)^2

So ∫[1/A]dx = [1/√3]arctan[(x-1)/√3] + C

Is this correct?

Thanks for any help