[tex]\int \frac{1}{x\sqrt{4x + 1}}dx[/tex](adsbygoogle = window.adsbygoogle || []).push({});

I let [tex]u= \sqrt{4x+1}[/tex], [tex]u^2 = 4x+1[/tex]

So [tex]\frac{1}{2}u du = dx[/tex]

[tex]\int \frac{\frac{1}{2}u}{(\frac{u^2-1}{4})*((\sqrt{u})^2)}du[/tex]

[tex]\int \frac{2u}{(u^2 - 1)*(u)} du[/tex]

[tex]\int \frac{2}{u^2 - 1} du[/tex]

[tex]2\int \frac{1}{u^2 -1}du[/tex]

Can anyone help me anti-differentiate what the integrand is?

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# Homework Help: Integration question

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