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i have been advised to used trig subsitution wherein i subsitute z = cos theta

however i end up at a dead end

[tex] \int \sqrt{10 \cos \theta - \cos^2 \theta} sin \theta d \theta [/tex]

i could certainly replace the sin

[tex] \int \sqrt{10 \cos \theta - \cos^2 \theta} \sqrt{1- \cos^2 \theta} d \theta [/tex]

hwat now do i expand?

or do i use parts?