trying to integrate [tex] \sqrt{10z-z^2} [/tex](adsbygoogle = window.adsbygoogle || []).push({});

i have been advised to used trig subsitution wherein i subsitute z = cos theta

however i end up at a dead end

[tex] \int \sqrt{10 \cos \theta - \cos^2 \theta} sin \theta d \theta [/tex]

i could certainly replace the sin

[tex] \int \sqrt{10 \cos \theta - \cos^2 \theta} \sqrt{1- \cos^2 \theta} d \theta [/tex]

hwat now do i expand?

or do i use parts?

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# Homework Help: Integration sqrt(10z - z^2)

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