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Integration / substitution

  1. May 29, 2009 #1
    1. The problem statement, all variables and given/known data

    http://img20.imageshack.us/img20/112/41590752.jpg [Broken]

    2. Relevant equations

    3. The attempt at a solution

    I have no idea how to convert the left equation into the right one.

    Could someone show me how to do that?

    I don't understand why the right equation should be multiplied by 1/2

    It is really giving me a headache.

    Thanks for reading this post.
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. May 29, 2009 #2


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    Gold Member

    substitute [tex]u=1 + \mu^2[/tex] therefore [tex]du=2 \mu d \mu[/tex] the half comes in becuase you have to solve for [tex] \mu d \mu[/tex] which is in the numerator, it becomes [tex]\frac{1}{2}du= \mu dx[/tex]

    since this the HW forum you should be able to see the rest.
  4. May 29, 2009 #3
    Thank you. Now I understand. :)
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