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I would like to ask you for help with one of the tasks from my assignment. The rest of the assignment is done including some simple integration but I struggle with this one:

Task

"The total load capacity for a circular hydrostatic bearing is given as

##W=\int_0^{R_o} p_r(2πr dr) + \int_{R_o}^R p(2πr dr) ##

By expressing the radial pressure in terms of the recess pressure, and by step by step argument, show that:

##W={\frac{π}{2}}{\frac{R^2-R_o^2}{2ln(R/R_o)}}p_r ## "

I think that radial pressure in terms of recess pressure is:

##p=p_r{\frac{ln(R/r)}{ln(R/R_o)}} ##

I really cannot get my head around it. Shall I just substitute above equation for 'p'? Then I would get:

##W=\int_0^{R_o} p_r(2πr dr) + \int_{R_o}^R{\frac{p_r2πrdrln(R/r)}{ln(R/R_o)}} ##

Do I have to then sort both integrals and just add them up together?