- #1
albalaka
- 2
- 0
I have been given the problem ∫√(ex-3)
and we must use the substitution u = √(ex-3)
I can start it off with u = √(ex-3)
and du = exdx/2u
and what I've been trying is to complete the square and go towards 2 ∫ u2du/((u2+4) -1)
But I am not getting towards the answer, either I am doing something wrong in the middle, or my approach is wrong.
the answer given is 2√(ex-3) - 2 √3 arctan(ex-3)/√3) +c
any help would really be appreciated, I've searched online trying to find a pattern, but i just can't figure it out
and we must use the substitution u = √(ex-3)
I can start it off with u = √(ex-3)
and du = exdx/2u
and what I've been trying is to complete the square and go towards 2 ∫ u2du/((u2+4) -1)
But I am not getting towards the answer, either I am doing something wrong in the middle, or my approach is wrong.
the answer given is 2√(ex-3) - 2 √3 arctan(ex-3)/√3) +c
any help would really be appreciated, I've searched online trying to find a pattern, but i just can't figure it out