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Integration-very simpleneed help fast!

  1. Feb 1, 2008 #1
    integration---very simple..need help fast!

    how to integrate 6e^-2t
  2. jcsd
  3. Feb 1, 2008 #2

    Ben Niehoff

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    Yes, it is very simple. What's confusing you about it, exactly?
  4. Feb 1, 2008 #3
    dont know how to do it..lyke integal of it is 6*-0.5*e^-2t?
  5. Feb 1, 2008 #4
    Looks right...
  6. Feb 1, 2008 #5
    so now suppose i want to put in values for t as 0 and 6..will i get the answer as 2.99?
  7. Feb 1, 2008 #6

    Ben Niehoff

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    No, not at all.

    Edit: No, wait, maybe. I read it wrong. I assume you know how to use a calculator, though...I don't see what you're asking help with anymore.
  8. Feb 1, 2008 #7
  9. Feb 1, 2008 #8
    Yes you will get something like 2.99998

  10. Feb 1, 2008 #9
    aaahhh sorryy its
  11. Feb 2, 2008 #10
    [tex]\int 6e^{-2x}dx=6\int e^{-2x}\frac{d(-2x)}{-2}=-3\int e^{-2x}d(-2x)=-3 e^{-2x}+C[/tex]
    where [tex]d(-2x)=-2dx[/tex]
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