How can I quickly integrate 6e^-2t using simple techniques?

  • Thread starter pinkyjoshi65
  • Start date
In summary, the conversation is about integrating 6e^-2t and putting in values for t as 0 and 6 to get a final answer. The answer is found to be 2.99998 when using the formula -3*(e^-2t)\int 6e^{-2x}dx=6\int e^{-2x}\frac{d(-2x)}{-2}=-3\int e^{-2x}d(-2x)=-3 e^{-2x}+C, where d(-2x)=-2dx.
  • #1
pinkyjoshi65
260
0
integration---very simple..need help fast!

how to integrate 6e^-2t
 
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  • #2
Yes, it is very simple. What's confusing you about it, exactly?
 
  • #3
dont know how to do it..lyke integal of it is 6*-0.5*e^-2t?
 
  • #4
Looks right...
 
  • #5
so now suppose i want to put in values for t as 0 and 6..will i get the answer as 2.99?
 
  • #6
No, not at all.

Edit: No, wait, maybe. I read it wrong. I assume you know how to use a calculator, though...I don't see what you're asking help with anymore.
 
  • #7
(e^-2t)/-3
 
  • #8
pinkyjoshi65 said:
so now suppose i want to put in values for t as 0 and 6..will i get the answer as 2.99?

Yes you will get something like 2.99998


(e^-2t)/-3

Huh?
 
  • #9
aaahhh sorryy its
-3*(e^-2t)
 
  • #10
[tex]\int 6e^{-2x}dx=6\int e^{-2x}\frac{d(-2x)}{-2}=-3\int e^{-2x}d(-2x)=-3 e^{-2x}+C[/tex]
where [tex]d(-2x)=-2dx[/tex]
[tex]dx=\frac{d(-2x)}{-2}[/tex]
 

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